Putting two checkers on 6 points gives you 21 different positions as you can seen at this table. So there are 21x21=441 different positions with two checkers versus two checkers in the bearoff. Easy to handle.
Calculating three versus three checkers in the bearoff is a bit more difficult. There are (n+k-1)!/(n-1)!k! possibilities to put k checkers on n points, so we have 56 different positions. Take your opponent into account and you get 56x56 = 3,136 different positions to consider. Of course there are a few positions like having 3 checkers on the acepoint versus 3 checkers on the 6-point which really don't matter. Still, it's quite a big bunch and too much for putting it into a concise table.
So I decided to divide it into different parts:
- General considerations (basics)
- Even pipcount with three checkers on both sides
- three checkers against three opponent checkers on the acepoint
- Opponent is leading by 4 pips
- Opponent is leading by 3 pips
- Opponent is leading by 2 pips
- Opponent is leading by 1 pip
- Opponent is trailing
Write a comment
- Required fields are marked with *.
